How do you solve #2v^2+20v=0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer marfre May 27, 2017 #v = 0, v = -10# Explanation: Given: #2v^2 + 20v = 0# Factor the GCF (what is common to both), #2v#: #2v(v + 10) = 0# #2v = 0; " and " v + 10 = 0# # (2v)/2 = 0/2; " and " v + 10 - 10 = -10# #v = 0; " and " v = -10# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1104 views around the world You can reuse this answer Creative Commons License