How do you solve $2x^2+7x+9=0$ ?

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Answer 1 · 2015-06-03T18:11:44

$2x^2+7x+9$ is of the form $ax^2+bx+c$ , with $a=2$ , $b=7$ and $c=9$ .

The discriminant $Delta$ is given by the formula:

$Delta = b^2-4ac = 7^2 - (4xx2xx9) = 49 - 72 = -23$

Since $Delta < 0$ the quadratic equation has no real roots. It has two distinct complex roots.

How do you solve 2x^2+7x+9=0 2x^2+7x+9=0?