How do you solve #2x - (3/4) + (4/3) = 8 + (4/3)#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Don't Memorise Aug 8, 2015 #color(blue)(x=35/8# Explanation: #2x - 3/4 + color(blue)(4/3) = 8 +color(blue)(4/3# #2x - 3/4 = 8 +color(blue)(4/3 - 4/3# #2x - 3/4 = 8 +0# #2x - 3/4 = 8 # #(2x*4)/4 - 3/4 = 8 # #(8x- 3)/4 = 8 # #8x- 3 = 8*4 # #8x- 3 = 32 # #8x = 32+3# #color(blue)(x=35/8# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1638 views around the world You can reuse this answer Creative Commons License