How do you solve #2x - (3/4) + (4/3) = 8 + (4/3)#?

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Answer 1 · 2015-12-05T03:21:10

#color(blue)(x=35/8#

#2x - (3/4) + (4/3) = 8 +(4/3)#

It can be observed that the term #4/3# is present on both the L.H.S and R.H.S, so it can be cancelled out.

#2x - (3/4) + cancel(4/3) = 8 +cancel(4/3)#

#2x - (3/4) = 8 #

#2x = 8 +(3/4)#

#2x = (8*4)/(1*4) +(3/4)#

#2x = (32)/(4) +3/4#

#color(blue)(2)x = (35/4)#

#x = (35/4) *color(blue)(1/2#

#color(blue)(x=35/8#