How do you solve (2x+3)/(x^2-9) + x/(x-3)2x+3x29+xx3?

1 Answer
Apr 3, 2018

(x^2+5x+3)/(x^2-9)x2+5x+3x29

Explanation:

Add them like fractions (make sure their denominators are the same)

The two denominators are x^2-9x29 are x-3x3. Find the least common denominator.

x^2-9=(x-3)(x+3) rarrx29=(x3)(x+3) One of the denominators is a factor of the other

Multiply the second fraction's numerator and denominator by x+3x+3 to get the same denominator as the first fraction

x/(x-3)*(x+3)/(x+3)xx3x+3x+3

(x^2+3x)/(x^2-9)x2+3xx29

Now add the fractions together

(2x+3+x^2+3x)/(x^2-9)2x+3+x2+3xx29

Combine like terms:

(x^2+5x+3)/(x^2-9)x2+5x+3x29