How do you solve #2x+3+x+5=11#?
1 Answer
Jun 14, 2017
Explanation:
#"collect terms in x on the left side of the equation and "#
#"numeric values on the right side"#
#rArr3x+8=11larr" collecting like terms on left side"#
#"subtract 8 from both sides"#
#3xcancel(+8)cancel(-8)=11-8#
#rArr3x=3#
#"divide both sides by 3"#
#(cancel(3) x)/cancel(3)=3/3#
#rArrx=1#
#color(blue)"As a check"# Substitute this value into the left side and if equal to the right side then it is the solution.
#(2xx1)+3+1+5=2+3+1+5=11=" right side"#
#rArrx=1" is the solution"#