How do you solve $2 x - 3 y = 24$ $2x-3y=24$ and $y + 7 x = 46$ $y+7x=46$ using substitution?

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How do you solve $2 x - 3 y = 24$ $2x-3y=24$ and $y + 7 x = 46$ $y+7x=46$ using substitution?

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Answer 1 · 2016-07-30T12:18:39

$x = \frac{162}{23}$ $x=162/23$
$y = - \frac{76}{23}$ $y=-76/23$

Explanation:

Multiplying both sides of the equation $y + 7 x = 46$ $y+7x=46$ by $3$ $3$
we get
$3 y + 21 x = 138$ $3y+21x=138$
$2 x - 3 y = 24$ $2x-3y=24$
Adding up both the above equations
we get
$3 y + 21 x + 2 x - 3 y = 138 + 24$ $3y+21x+2x-3y=138+24$
or
$23 x = 162$ $23x=162$
or
$x = \frac{162}{23}$ $x=162/23$
From the equation $y + 7 x = 46$ $y+7x=46$
we get
$y = 46 - 7 x$ $y=46-7x$
or
$y = 46 - 7 (\frac{162}{23})$ $y=46-7(162/23)$
or
$y = 46 - \frac{1134}{23}$ $y=46-1134/23$
or
$y = \frac{46 (23) - 1134}{23}$ $y=(46(23)-1134)/23$
or
$y = \frac{1058 - 1134}{23}$ $y=(1058-1134)/23$
or
$y = - \frac{76}{23}$ $y=-76/23$

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How do you solve $2 x - 3 y = 24$ $2x-3y=24$ and $y + 7 x = 46$ $y+7x=46$ using substitution?

1 Answer

Explanation:

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How do you solve $2 x - 3 y = 24$ $2x-3y=24$ and $y + 7 x = 46$ $y+7x=46$ using substitution?