How do you solve $2 x^{4} + 2 x^{3} + x^{2}$ $2x^4 + 2x^3 + x^2$ when x = 7?

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Answer 1 · 2018-07-06T04:18:22

$5537$ $5537$

Given: $2 x^{4} + 2 x^{3} + x^{2}$ $2x^4 + 2x^3 + x^2$ let $x = 7$ $x = 7$

$2 {(7)}^{4} + 2 {(7)}^{3} + {(7)}^{2}$ $2(7)^4 + 2(7)^3 + (7)^2$

$= 4802 + 686 + 49$ $= 4802 + 686 + 49$

$= 5537$ $= 5537$

How do you solve 2x^4 + 2x^3 + x^22x4+2x3+x22x^4 + 2x^3 + x^2 when x = 7?