How do you solve #2x+4<3x+9#?
1 Answer
Jul 18, 2017
Explanation:
#"subtract 2x from both sides"#
#cancel(2x)cancel(-2x)+4<3x-2x+9#
#rArr4 < x+9#
#"subtract 9 from both sides"#
#4-9 < xcancel(+9)cancel(-9)#
#rArr-5 < x#
#rArrx> -5#
