Question

How do you solve `2x+4<3x+9`?

Answer 1

`x> -5`

Explanation:

`"subtract 2x from both sides"`

`cancel(2x)cancel(-2x)+4<3x-2x+9`

`rArr4 < x+9`

`"subtract 9 from both sides"`

`4-9 < xcancel(+9)cancel(-9)`

`rArr-5 < x`

`rArrx> -5`