How do you solve #2x = 4# and #2x – y = 5#?
1 Answer
Aug 21, 2015
Explanation:
Notice that you can find the value of
#(color(red)(cancel(color(black)(2))) * x)/color(red)(cancel(color(black)(2))) = 4/2#
#x = color(green)(2)#
Now simply take this value of
#2x - y = 5#
#2 * (2) - y = 5#
#4 - y = 5#
This is equivalent to
#y = 4 -5 = color(green)(-1)#