How do you solve $2 x + 5 y = 11$ $2x+5y=11$ and $4 x + 3 y = 1$ $4x+3y=1$ using substitution?

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Answer 1 · 2018-03-05T16:01:29

$y = 3, x = - 2$ $y=3,x=-2$

We have $2 x = 11 - 5 y$ $2x=11-5y$

Multiplying both sides by $2$ $2$ ,we get $4 x = 22 - 10 y$ $4x=22-10y$

substituting this value in $2$ $2$ nd equation,we have,

$22 - 10 y = 1 - 3 y$ $22-10y=1-3y$

Or, $21 = 7 y$ $21=7y$

Thus,we get, $y = 3$ $y=3$ and substituting this value in first equation we get $x$ $x$ as $- 2$ $-2$

How do you solve 2x+5y=112x+5y=11 and 4x+3y=14x+3y=1 using substitution?