How do you solve $2 x - y = - 10$ $2x-y=-10$ and $2 x - 4 y = - 4$ $2x-4y=-4$ ?

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Answer 1 · 2016-05-06T20:37:22

$x = - \frac{5}{2}$ $x=-5/2$

$y = - 2$ $y=-2$

$2 x - y = - 10 2 x = y - 10 (1)$ $2x-y=-10" "color(red)(2x)=y-10" (1)"$

$2 x - 4 y = - 4 2 x = 4 y - 4 (2)$ $2x-4y=-4" "color(red)(2x)=4y-4" (2)"$

$(1) = (2)$ $(1)=(2)$

$y - 10 = 4 y - 4$ $y-10=4y-4$

$- 10 + 4 = 4 y - y$ $-10+4=4y-y$

$- 6 = 3 y$ $-6=3y$

$y = - \frac{6}{3}$ $y=-6/3$

$y = - 2$ $y=-2$

$using (1) or (2)$ $"using (1) or (2)"$

$2 x = y - 3$ $2x=y-3$

$2 x = - 2 - 3$ $2x=-2-3$

$2 x = - 5$ $2x=-5$

$x = - \frac{5}{2}$ $x=-5/2$

How do you solve 2x−y=−102x-y=-10 and 2x−4y=−4 2x-4y=-4?