How do you solve 2x + y = 52x+y=5 and y = 3x + 2y=3x+2 using substitution?

2 Answers
Jul 30, 2016

x=3/5x=35
y=19/5y=195

Explanation:

2x+y=52x+y=5
Putting y=3x+2y=3x+2 in the above equation we get
2x+3x+2=52x+3x+2=5
or
5x+2=55x+2=5
or
5x=5-25x=52
or
5x=35x=3
or
x=3/5x=35=======Ans 11
By putting x=3/5x=35 in the equation y=3x+2y=3x+2
we get
y=3(3/5)+2y=3(35)+2
or
y=9/5+2y=95+2
or
y=(9+2(5))/5y=9+2(5)5
or
y=(9+10)/5y=9+105
or
y=19/5y=195=====Ans 22

Jul 30, 2016

x = 3/5, y = 3 4/5x=35,y=345

Explanation:

This type of question is particularly common when working with straight lines.

Note that there is a single yy term in both equations.

y = -2x+5" and " y = 3x +2y=2x+5 and y=3x+2

At the point where the two lines intersect, the x- and y-xandy values are equal.

If " y = y" " y = y it follows that:

3x +2 =-2x+53x+2=2x+5

5x = 35x=3

x = 3/5x=35

There are now two equations to find a value for y. If we get the same answer for each we will know our answers are correct.

y = 3xx 3/5 +2 = 3 4/5" "y = -2 xx3/5 +5 = 3 4/5y=3×35+2=345 y=2×35+5=345