How do you solve $2y = 4x - 16$ and $5y = 4x + 8$ ?

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Answer 1 · 2016-05-03T06:42:36

Okay we will solve this step by step

Let $2y=4x-16$ be equation number 1
and $5y=4x+8$ be equation number 2

$4x$ is same in both equations that is to say has same coefficient $4x$

So we will subtract both of them
$+5y=+4x+8$
$-2y=-4x +16$
This results in
$3y=24$
$y=8$ Substituting this value in equation number 2

$5(8)=4x+8$
$40=4x+8$
$40-8=4x$
$32=4x$
$32/4=x$
$8=x$

So we get $x=8$ and $y=8$

Cheers

How do you solve 2y = 4x - 16 2y = 4x - 16 and 5y = 4x + 85y = 4x + 8?