How do you solve $(3^{4} \div 9) + 32 - (5 \times 10) + 6$ $(3^{4} \div 9) + 32- ( 5\times 10) + 6$ ?

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Answer 1 · 2018-03-29T13:19:57

See below.

To simplify this expression, we need to use a process called the Order of Operations.

This is more commonly known as $P E M D A S$ $PEMDAS$ , an acronym to describe the necessary steps (in order) of solving such an expression:

$P$ $P$ - Parenthesis

$E$ $E$ - Exponents

$M D$ $MD$ - Multiply/Divide (Left to right)

$A S$ $AS$ - Add/Subtract (Left to right)

Knowing this, we can being to simplify:

$(3^{4} \div 9) + 32 - (5 \times 10) + 6$ $(3^4divide9)+32-(5times10)+6$

$= (81 \div 9) + 32 - (5 \times 10) + 6$ $=(81divide9)+32-(5times10)+6$

$= (9) + 32 - (50) + 6$ $=(9)+32-(50)+6$

$= 41 - (50) + 6$ $=41-(50)+6$

$= - 9 + 6$ $=-9+6$

$= - 3$ $=-3$

How do you solve (3^{4} \div 9) + 32- ( 5\times 10) + 6(34÷9)+32−(5×10)+6(3^{4} \div 9) + 32- ( 5\times 10) + 6?