Question

How do you solve `3/4 x + 2>20`?

Answer 1

See the entire solution process below:

Explanation:

First, subtract `color(red)(2)` from each side of the inequality to isolate the `x` term while keeping the inequality balanced:

`3/4x + 2 - color(red)(2) > 20 - color(red)(2)`

`3/4x + 0 > 18`

`3/4x > 18`

Now, multiply each side of the inequality by `color(red)(4)/color(blue)(3)` to solve for `x` while keeping the inequality balanced:

`color(red)(4)/color(blue)(3) xx 3/4x > color(red)(4)/color(blue)(3) xx 18`

`cancel(color(red)(4))/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(3)))/color(red)(cancel(color(black)(4)))x > color(red)(4)/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(18))) 6`

`x > 4 xx 6`

`x > 24`