How do you solve #(3(t-1/3))/2-4=6#?

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Answer 1 · 2018-05-15T23:27:52

#t=7#

#(3(t-1/3))/2-4=6#
we want to isolate t

since the term containing t has 4 subtracted from it, we add 4 to both sides

adding 4 to both sides:
#(3(t-1/3))/2=10#

multiply both sides by 2 to get
#3(t-1/3)=20#

the term containing t is being multiplied by 3, so we can divide both sides by 3 to get

#(t-1/3)=20/3#

finally, #1/3# is being subtracted from t so we can add #1/3# to both sides to get

t = #21/3=7#