#3/(x^2-4) = (2(x-2)+x(x+2))/(x^2-4)#or #2x-4+x^2+2x-3=0 or x^2+4x-7=0#This is a quadratic equation of form #ax^2+bx+c; a=1 ; b=4; c=-7#
roots are real as #b^2-4ac# is positive. Roots are #-b/(2a)+- sqrt (b^2-4ac)/(2a) = -4/2+-sqrt44/2 = 1.317, -5.317#[Ans]