How do you solve #3/(x+2)=6/(x-1)#?
1 Answer
May 17, 2017
Explanation:
#"one way is to use the method of "color(blue)"cross-multiplication"#
#"given " a/b=c/d" then " ad=bc#
#"applying this to the equation"#
#6(x+2)=3(x-1)#
#6x+12=3x-3larr" distributing"#
#"subtract 3x from both sides"#
#6x-3x+12=cancel(3x)cancel(-3x)-3#
#rArr3x+12=-3#
#"subtract 12 from both sides"#
#3xcancel(+12)cancel(-12)=-3-12#
#rArr3x=-15#
#"divide both sides by 3"#
#(cancel(3) x)/cancel(3)=(-15)/3#
#rArrx=-5#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left side "=3/(-5+2)=3/(-3)=-1#
#"right side " =6/(-5-1)=6/(-6)=-1#
#rArrx=-5" is the solution"#