How do you solve #3/(x+3) - 4/(x-3) = (5x)/(x^2-9)#?

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Answer 1 · 2016-08-03T01:45:52

#x=-7/2#

#3/(x+3) - 4/(x-3) = (5x)/(x^2-9)#

#(3(x-3)-4(x+3))/(x^2-9) = (5x)/(x^2-9)#

For #x!= +-3#:
#(3(x-3)-4(x+3))/cancel(x^2-9) = (5x)/cancel(x^2-9)#

#3(x-3)-4(x+3) = 5x#

#3x-9-4x-12 = 5x#

#-6x=21#

#x=-7/2#