How do you solve $3 (x - 5) = 6$ $3(x-5)=6$ ?

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Answer 1 · 2016-11-16T22:58:26

$x = 7$ $x = 7$

Step 1) Expand the terms in parenthesis, in this case only on the left side of the equation:

$3 x - 15 = 6$ $3x - 15 = 6$

Step 2) Solve for $x$ $x$ using the necessary mathematics while keeping the equation balanced:

$3 x - 15 + 15 = 6 + 15$ $3x - 15 + 15 = 6 + 15$

$3 x - 0 = 21$ $3x - 0 = 21$

$3 x = 21$ $3x = 21$

$\frac{3 x}{3} = \frac{21}{3}$ $(3x)/3 = 21/3$

$x = 7$ $x = 7$

How do you solve 3(x-5)=63(x−5)=63(x-5)=6?