How do you solve #3/(z+7)=2/(z-4)#?

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Answer 1 · 2016-03-17T14:28:30

#z=26#

#color(blue)(3/(z+7)=2/(z-4)#

Cross multiply #color(brown)(a/b=c/d,ad=bc#

#rarr3(z-4)=2(z+7)#

Use distributive property #color(brown)(a(b+c)=ab+ac#

#rarr3z-12=2z+14#

#rarr3z-2z=14+12#

#rarrz=14+12#

#color(green)(rArrz=26#

Check

#color(indigo)(3/(26+7)=2/(26-4)#

#color(indigo)(3/33=2/22#

#color(indigo)(1/11=1/11#