First, subtract #color(red)(3b)# and #color(blue)(15)# from each side of the inequality to isolate the #b# term while keeping the inequality balanced:
#3b - 6 - color(red)(3b) - color(blue)(15) >= 15 + 24b - color(red)(3b) - color(blue)(15)#
#3b - color(red)(3b) - 6 - color(blue)(15) >= 15 - color(blue)(15) + 24b - color(red)(3b)#
#0 - 21 >= 0 + (24 - color(red)(3))b#
#-21 >= 21b#
Now, divide each side of the inequality by #color(red)(21)# to solve for #b# while keeping the inequality balanced:
#-21/color(red)(21) >= (21b)/color(red)(21)#
#-1 >= (color(red)(cancel(color(red)(21)))b)/cancel(color(red)(21))#
#-1 >= b#
To state the solution in terms of #b# we can reverse or "flip" the entire inequality:
#b <= -1#
