How do you solve #3d + 2< 5d - 2( d + 1)#? Algebra Linear Inequalities and Absolute Value Inequalities with Addition and Subtraction 1 Answer Hieu N. · Stefan V. Jan 26, 2018 #2 < -2#, which is a false inequality. Explanation: We can distribute #-2(d+1)# #3d + 2 < 5d - 2d - 2 # Combine like terms #3d + 2 < 3d - 2# Subtract both sides by #3d#, which gives you #2 < -2# Well, #2# can not be less than #-2#, so it is a false inequality. Answer link Related questions Does the inequality sign change when you are you subtracting? How do you solve inequalities with addition and subtraction? How do you solve inequalities with fractions? How do you solve #15 + g \ge -60#? How do you graph #x + 65 < 100#? How do you solve the inequality #5 + t \ge \frac{3}{4}#? How do you graph the inequality #x - 1 > -10# on a number line? Why do you not change the inequality sign when you are adding or subtracting? What's the result when you raise a number to the zero power? How do you solve #x+ 3 < 2#? See all questions in Inequalities with Addition and Subtraction Impact of this question 1427 views around the world You can reuse this answer Creative Commons License