How do you solve #3d + 2< 5d - 2( d + 1)#?

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Answer 1 · 2018-01-26T03:58:43

#2 < -2#, which is a false inequality.

We can distribute #-2(d+1)#

#3d + 2 < 5d - 2d - 2 #

Combine like terms

#3d + 2 < 3d - 2#

Subtract both sides by #3d#, which gives you

#2 < -2#

Well, #2# can not be less than #-2#, so it is a false inequality.