Question

How do you solve `3e^(-b)=56`?

Answer 1

`b=-2.9268`

Explanation:

As `3e^(-b)=56`, we have

`3/e^b=56` or

`3=56e^b` or

`e^b=3/56` and taking natural logarithm on both sides

`b=ln3-ln56=1.0986-4.0254=-2.9268`