How do you solve 3m2−5m−7=−5?

1 Answer
Lucy
Jun 20, 2018

m=−13 or m=−2

Explanation:

3m2−5m−7=−5
3m2−5m−7+5=0
3m2−5m−2=0

Using either the criss cross method or the quadratic formula, you would get the answer
(3m+1)(m−2)=0 so m=−13 or m=−2

Using the quadratic formula,

m=−b±√b2−4ac2a where your general form is given by am2+bm+c=0

m=5±√25+246

m=5±√496

m=5±76

m=5−76 or m=5+76

m=−13 or m=2

(m−(−13))(m−2)=0

Which can then be put into the following form
(m+13)(m−2)=0

(3m+1)(m−2)=0

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