Question

How do you solve `3p - 6 > 21`?

Answer 1

`p>9`

Explanation:

`"isolate "3p" by adding 6 to both sides"`

`3pcancel(-6)cancel(+6)>21+6`

`3p>27`

`"divide both sides by 3"`

`p>9" is the solution"`

`p in(9,oo)larrcolor(blue)"in interval notation"`