Question

How do you solve `3x + 2 ≤ 1`?

Answer 1

`x <= -1/3`

Explanation:

Things you can do with expressions in an inequality which maintain the inequality:

• Add the same amount to each expression
• Subtract the same amount from each expression
• Divide each expression by the same amount provided the amount is greater than zero
• Multiply each expression by the same amount provided the amount is greater than zero

Therefore, given
`color(white)("XXX")3x+2 <= 1`

We can subtract `2` from both sides:
`color(white)("XXX")3x <= -1`

and, we can divide both sides by `3`
`color(white)("XXX")x <= -1/3`