How do you solve #3x^2=x+4# by factoring?

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Answer 1 · 2016-10-26T06:28:06

#x=1 1/3#, #-1#

#3x^2=x+4#

Shift all the terms to the left.

#3x^2-x-4=0#

Factorise.

#3x^2+3x-4x-4=0#

#3x(x+1)-4(x+1)=0#

#(3x-4)(x+1)=0#

#3x-4=0# and #x+1=0#

#x=4/3 = 1 1/3# and #x=-1#