How do you solve 3x+2y=16 and 2x+3y=14?

1 Answer
Sep 10, 2016

Solution is x=4 and y=2

Explanation:

When we have such linear equations, where we have addition only and coefficients of x and y reversed (i.e. of the type ax+by=c and bx+ay=d), we can just add the two equations to get one equation and then subtract one from other to get another, which when simplified become equations of the type x+y=m and xy=n and easier to solve,

Here we have 3x+2y=16 and 2x+3y=14

adding them gives 4x+5y=30 or x+y=6

subtracting second from first gives xy=2

Now as x+y=6 and xy=2, adding them we get 2x=8 or x=4.

And y=64=2

Hence solution is x=4 and y=2