How do you solve #3x + 3y = –6# and #–x + y = 0#?

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Answer 1 · 2015-08-04T05:37:20

The solution for the system of equations is:
#color(blue)(x=-1,y=-1#

# 3x+3y=–6 #.....equation #(1)#

#–x+y=0#
#x=color(blue)(y#........equation #(2)#

Solving through substitution:

Substituting equation #2# in equation #1#
# 3x+3y=–6 #

# 3 * color(blue)(y)+3y=–6 #

# 6y=–6 #

# color(blue)(y=–1 #

From equation #2# we know that : #x=y#
So , #color(blue)(x=-1#