How do you solve $3 x + 4 y = 15$ $3x +4y = 15$ and $3 x + 2 y = 12$ $3x + 2y = 12$ ?

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How do you solve $3 x + 4 y = 15$ $3x +4y = 15$ and $3 x + 2 y = 12$ $3x + 2y = 12$ ?

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Answer 1 · 2018-06-08T17:57:53

$x = 3, y = \frac{3}{2}$ $x=3,y=3/2$

Explanation:

Multiplying the second equation by $- 1$ $-1$ and adding to the first we get
$2 y = 3$ $2y=3$ so $y = \frac{3}{2}$ $y=3/2$
plugging this in the second equation

$3 x + 3 = 12$ $3x+3=12$
so
$3 x = 9$ $3x=9$
$x = 3$ $x=3$

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How do you solve $3 x + 4 y = 15$ $3x +4y = 15$ and $3 x + 2 y = 12$ $3x + 2y = 12$ ?

1 Answer

Explanation:

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How do you solve $3 x + 4 y = 15$ $3x +4y = 15$ and $3 x + 2 y = 12$ $3x + 2y = 12$ ?