How do you solve 3x+4y=22 and x-5y=-37?

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Answer 1 · 2015-09-09T06:08:32

The solution for the system of equations is
#color(blue)(x=-2, y=7#

#color(blue)(3x)+4y=22#...........equation #(1)#

# x-5y=-37#, multiplying this equation by #3#
# color(blue)(3x)-15y=-111#....equation #(2)#

Now we can solve using the method of elimination .

Subtracting equation #2# from #1# eliminates #color(blue)(3x#

#color(blue)(3x)+4y=22#
# -cancelcolor(blue)(3x)+15y=+111#

#19y = 133#
#color(blue)(y=7#

Now we find #x# by substituting #y# in equation #1#
#3x+4y=22#

#3x=22 -4y#

#3x=22 -4*7#

#3x=22 -28#

#3x = -6#
#color(blue)(x=-2#