Question

How do you solve `3x² + 5x = 2`?

Answer 1

`x_1=-2`
`x_2=1/3`

Explanation:

`3x^2+5x=2`
`3x^2+5x-2=0`
`ax^2+bx+c=0`
`Delta=sqrt(b^2-4*a*c)`
`Delta=sqrt(5^2+4*3*2)`
`Delta=sqrt(25+24)" "Delta =sqrt49 " "Delta=±7`
`x_"1,2"=(-b±Delta)/(2*a)`
`x_1=(-b-Delta)/(2*a)=(-5-7)/(2*3)=(-12)/6`
`x_1=-2`
`x_2=(-b+Delta)/(2*a)=(-5+7)/(2*3)=2/6`
`x_2=1/3`