Question

How do you solve `3x-y=12` and `5x+2y=20`?

Answer 1

`x=4; y =0`

Explanation:

`3*x-y = 12 (1)`
`5*x+2*y=20 (2)`
Multiplying (1) by 2 we get
`6*x-2*y=24` (1)
`5*x+2*y=20 (2)`
Adding (1) & (2) we get
`11*x=44 or x=4` putting x=4 in (1) we get `y=3*4-12 = 0`
So `x=4; y =0` ;[Answer]