How do you solve #3x-y=3# and #-2x+y=2#?

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Answer 1 · 2015-08-02T23:12:28

#color(red)( x=5,y=12)#

One way is to use the method of elimination.

Step 1. Enter the equations.

[1] #3x-y=3#
[2] #-2x+y=2#

Step 2. Add the equations.

[3] #x=5#

Step 3. Substitute Equation 3 in Equation 2.

#-2x+y=2#

#-2(5)+y=2#

#-10+y =2#

#y=12#

Solution: #x=5,y=12#

Check: Substitute the values of #x# and #y# in Equation 1.

#3x-y=3 #
#3(5)-12=3#
#15-12=3#
#3=3#