How do you solve #-3x+y=-4# and #y=x-6#?

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Answer 1 · 2016-04-12T01:53:13

Since one variable is already isolated, it will be easiest to solve by substitution.

#y = x - 6 -> -3x + (x - 6) = -4#

#-3x + x - 6 = -4#

#-2x = 2#

#x = -1#

#y = -1 - 6#

#y = -7#

Thus, your solution set is #{-1,-7}#. Don't forget to present your solution set in the form #{x, y}#.

Hopefully this helps!