How do you solve 3y = 14 + x and x + 22 = 5y?

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Answer 1 · 2015-09-09T06:12:54

The solution for the system of equations is
#color(blue)(x=-2, y=4#

#3y = 14 + x#....equation #(1)#

#x + 22 = 5y#
#x=color(blue)( 5y-22#......equation #(2)#

We can solve using the method of substitution.
Substituting equation #2# in equation #1#:

#3y = 14 + x#

#3y = 14 +color(blue)( 5y-22#

#3y = -8+ 5y#
# 8 = 5y- 3y#

#2y=8#
#color(blue)(y=4#

Now we find #x# by substituting #y# in equation 2:
#x= 5y-22#

#x= 5*4-22#

#x= 20-22#

#color(blue)(x=-2#