How do you solve $\frac{4 + (- 10) \div 2}{{(7 - 8)}^{2}}$ $(4+(-10)-:2)/(7-8)^2$ ?

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Answer 1 · 2018-03-18T12:29:58

Answer is $- 1$ $-1$

First simplify the brackets and then apply $B O D M A S$ $BODMAS$

$\frac{4 - 10 \div 2}{{(- 1)}^{2}}$ $(4-10÷2)/(-1)^2$

$\frac{4 - 5}{1}$ $(4-5)/1$

$4 - 5$ $4-5$

$- 1$ $-1$

How do you solve 4+(−10)÷2(7−8)2(4+(-10)-:2)/(7-8)^2?