How do you solve #4<c/5#?

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Answer 1 · 2017-02-01T13:08:14

See the entire solution process below:

Multiply each side of the inequality by #color(red)(5)# to solve for #c# while keeping the inequality balanced:

#color(red)(5) xx 4 < color(red)(5) xx c/5#

#20 < cancel(color(red)(5)) xx c/color(red)(cancel(color(black)(5)))#

#20 < c#

To solve in terms of #c# we must reverse or "flip" the inequality:

#c > 20#