How do you solve 4 x ^2 − 15 x = 3 ?

2 Answers
May 9, 2018

x=(15+-sqrt273)/8

Explanation:

4x^2-15x=3

4x^2-15x-3=0

Use the quadratic formula

x=(-b+-sqrt(b^2-4ac))/(2a)

with a=4, b=-15, c=-3

x=(-(-15)+-sqrt((-15)^2-4(4)(-3)))/(2(4))=(15+-sqrt(225+48))/8=(15+-sqrt273)/8

May 9, 2018

4x^2-15x=3
4x^2-15x-3=0
D= β^2-4αγ
D= 15^2-4*4*-3
D= 225+48
D= 273

x1,2=(-β+- sqrt273)/(2α)
x1,2=(15+- sqrt273)/8
x1=(15+ sqrt273)/8
x2=(15- sqrt273)/8