How do you solve #4(x-2)=8(4-x)+12#? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Don't Memorise Feb 14, 2016 #x = 13/3# Explanation: #4(x-2) = 8 (4-x)+12# #4(x) + 4 (-2) = 8 (4) + 8 (-x)+12# #4x -8 = 32 -8x+12# #4x +8x = 32 +8+12# #12x = 52# #x = 52/12# #x = 13/3# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 1608 views around the world You can reuse this answer Creative Commons License