How do you solve #43(3x+1)-(x-1)=6(x+10)#?

1 Answer
Patrick H.
Jul 27, 2016

See explanation

Explanation:

Use the distributive property to get #129x+43-x+1=6x+60#. Combine like terms to get #128x +44=6x+60#. Subtract 44 from each side to get #128x=6x+16#. Subtract 6x from each side to get #122x=16#. Divide each side by 122 to get #x=8/61#.

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