How do you solve ${(45 - 37)}^{3} \div 4 \times 3 - 75$ $(45- 37)^{3} \div 4\times 3- 75$ ?

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How do you solve ${(45 - 37)}^{3} \div 4 \times 3 - 75$ $(45- 37)^{3} \div 4\times 3- 75$ ?

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Answer 1 · 2016-09-24T21:15:19

Follow the order of operations as indicated by PEMDAS.

Explanation:

The acronym PEMDAS can help us to remember the order of operations.

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Simplify: ${(45 - 37)}^{3} \div 4 \times 3 - 75$ $(45-37)^3-:4xx3-75$

Simplify the terms inside the parentheses first.

$8^{3} \div 4 \times 3 - 75$ $8^3-:4xx3-75$

Simplify $8^{3}$ $8^3$ .

$512 \div 4 \times 3 - 75$ $512-:4xx3-75$

Divide $512$ $512$ by $4$ $4$ .

$128 \times 3 - 75$ $128xx3-75$

Multiply $128$ $128$ by $3$ $3$ .

$384 - 75$ $384-75$

Subtract $75$ $75$ from $384$ $384$ .

$309$ $309$

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How do you solve ${(45 - 37)}^{3} \div 4 \times 3 - 75$ $(45- 37)^{3} \div 4\times 3- 75$ ?

1 Answer

Explanation:

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How do you solve (45−37)3÷4×3−75(45- 37)^{3} \div 4\times 3- 75?

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Explanation:

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How do you solve ${(45 - 37)}^{3} \div 4 \times 3 - 75$ $(45- 37)^{3} \div 4\times 3- 75$ ?