How do you solve $4d + 7 = - (2d + 41)$ ?

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Answer 1 · 2015-12-01T21:47:21

$d=-8$

Distribute the negative sign on the right side.

$4d+7=-2d-41$

Subtract $7$ from both sides.

$4d+7-7=-2d-41-7$

$4d=-2d-48$

Add $2d$ to both sides.

$4d+2d=-2d+2d-48$

$6d=-48$

Divide both sides by $6$ .

$(6d)/6=(-48)/6$

$d=-8$

How do you solve 4d + 7 = - (2d + 41)4d + 7 = - (2d + 41)?