Question

How do you solve `4p<32`?

Answer 1

`p<8`

Explanation:

We are solving for `p` so we divide both sides by `4` so `p` stands alone

`4p<32`

`(cancel(4)p)/cancel4<32/4`

`p<(4*8)/4`

`p<(cancel(4)*8)/cancel4`

`p<8`