Question

How do you solve `4x^2 <(12x-9)`?

Answer 1

`4x^2<12x-9` does not have any solution.

Explanation:

`4x^2<12x-9`

`hArr4x^2-12x+9<0` or

`(2x)^2-2×2x×3+3^2<0` or

`(2x-3)^2<0` i.e. `(2x-3` is negative.

But a square number can not be negative.

Hence `4x^2<12x-9` does not have any solution.