How do you solve $4 x + 2 y = 12$ $4x + 2y = 12$ and $x + 2 y = 6$ $x + 2y = 6$ ?

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Answer 1 · 2016-05-02T15:55:58

The solution for the system of equations is:
$x = 2$ $color(blue)(x =2$
$y = 2$ $color(blue)(y = 2$

$4 x + 2 y = 12$ $4x + color(blue)(2y) = 12$ ........equation $(1)$ $(1)$
$x + 2 y = 6$ $x + color(blue)(2y) = 6$ ..............equation $(2)$ $(2)$

Solving by elimination:

Subtracting equation $2$ $2$ from $1$ $1$ eliminates $2 y$ $color(blue)(2y$

$4x + cancelcolor(blue)(2y) = 12$
$- x - cancelcolor(blue)(2y) = - 6$

$3x = 6$

$x = 6/3$

$color(blue)(x =2$

Finding $y$ from equation $1$ :
$4x + 2y = 12$

$2y = 12 - 4x$

$2y = 12 - 4 * color(blue)(2$

$2y = 12 - 8$

$2y = 4$

$y = 4/2$

$color(blue)(y = 2$

How do you solve 4x + 2y = 124x+2y=124x + 2y = 12 and x + 2y = 6x+2y=6x + 2y = 6?