How do you solve #-4x+3<=-5+11#?

Question

1968 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-25T00:39:50

#x >= -3/4#

#-4x + 3 <= -5 + 11#

Simplify the right side:
#-4x + 3 <= 6#

Add #color(blue)(4x)# to both sides:
#-4x + 3 quadcolor(blue)(+quad4x) <= 6 quadcolor(blue)(+quad4x)#

#3 <= 6 + 4x#

Subtract #color(blue)6# from both sides:
#3 quadcolor(blue)(-quad6) <= 6 + 4x quadcolor(blue)(-quad6)#

#-3 <= 4x#

Divide both sides by #color(blue)4#:
#(-3)/color(blue)4 <= (4x)/color(blue)4#

#-3/4 <= x#

Therefore,
#x >= -3/4#

Hope this helps!