How do you solve #(4x-3)/(6-7x)+18=-3#?

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Answer 1 · 2016-08-06T21:41:02

#x = 123/143#

#(4x-3)/(6-7x)+18=-3#

#(4x-3)/(6-7x)=-3-18#

#(4x-3)/(6-7x) = (-21)/1 " cross multiply"#

#-21(6-7x)= 4x -3 #

#-126 +147x = 4x -3#

#143x =-3+126#

#143x = 123#

#x = 123/143#

Answer 2 · 2016-09-04T13:55:23

#x = (123) / (143)#

We have: #(4 x - 3) / (6 - 7 x) + 18 = - 3#

First, let's subtract #18# from both sides of the equation:

#=> (4 x - 3) / (6 - 7 x) = - 21#

Then. let's multiply both sides by #6 - 7 x#:

#=> 4 x - 3 = - 21 (6 - 7 x)#

#=> 4 x - 3 = - 126 + 147 x#

Let's collect the terms containing #x# on one side:

#=> 143 x = 123#

Finally, let's solve for #x# by dividing both sides by #143#:

#=> x = (123) / (143)#