How do you solve $\frac{4 x - 3}{6 - 7 x} + 18 = - 3$ $(4x-3)/(6-7x)+18=-3$ ?

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Answer 1 · 2016-08-06T21:41:02

$x = \frac{123}{143}$ $x = 123/143$

$\frac{4 x - 3}{6 - 7 x} + 18 = - 3$ $(4x-3)/(6-7x)+18=-3$

$\frac{4 x - 3}{6 - 7 x} = - 3 - 18$ $(4x-3)/(6-7x)=-3-18$

$\frac{4 x - 3}{6 - 7 x} = \frac{- 21}{1} cross multiply$ $(4x-3)/(6-7x) = (-21)/1 " cross multiply"$

$- 21 (6 - 7 x) = 4 x - 3$ $-21(6-7x)= 4x -3$

$- 126 + 147 x = 4 x - 3$ $-126 +147x = 4x -3$

$143 x = - 3 + 126$ $143x =-3+126$

$143 x = 123$ $143x = 123$

$x = \frac{123}{143}$ $x = 123/143$

Answer 2 · 2016-09-04T13:55:23

$x = \frac{123}{143}$ $x = (123) / (143)$

We have: $\frac{4 x - 3}{6 - 7 x} + 18 = - 3$ $(4 x - 3) / (6 - 7 x) + 18 = - 3$

First, let's subtract $18$ $18$ from both sides of the equation:

$\Rightarrow \frac{4 x - 3}{6 - 7 x} = - 21$ $=> (4 x - 3) / (6 - 7 x) = - 21$

Then. let's multiply both sides by $6 - 7 x$ $6 - 7 x$ :

$\Rightarrow 4 x - 3 = - 21 (6 - 7 x)$ $=> 4 x - 3 = - 21 (6 - 7 x)$

$\Rightarrow 4 x - 3 = - 126 + 147 x$ $=> 4 x - 3 = - 126 + 147 x$

Let's collect the terms containing $x$ $x$ on one side:

$\Rightarrow 143 x = 123$ $=> 143 x = 123$

Finally, let's solve for $x$ $x$ by dividing both sides by $143$ $143$ :

$\Rightarrow x = \frac{123}{143}$ $=> x = (123) / (143)$

How do you solve 4x−36−7x+18=−3(4x-3)/(6-7x)+18=-3?